Adafruit-circuitpython-ms8607

Latest version: v1.1.2

Safety actively analyzes 685525 Python packages for vulnerabilities to keep your Python projects secure.

Scan your dependencies

Page 2 of 4

1.0.17

To use in CircuitPython, simply install the [Adafruit CircuitPython Bundle](https://circuitpython.org/libraries).

To use in CPython, `pip3 install adafruit-circuitpython-ms8607`.

Read the [docs](http://circuitpython.readthedocs.io/projects/ms8607/en/latest/) for info on how to use it.

1.0.16

To use in CircuitPython, simply install the [Adafruit CircuitPython Bundle](https://circuitpython.org/libraries).

To use in CPython, `pip3 install adafruit-circuitpython-ms8607`.

Read the [docs](http://circuitpython.readthedocs.io/projects/ms8607/en/latest/) for info on how to use it.

1.0.15

To use in CircuitPython, simply install the [Adafruit CircuitPython Bundle](https://circuitpython.org/libraries).

To use in CPython, `pip3 install adafruit-circuitpython-ms8607`.

Read the [docs](http://circuitpython.readthedocs.io/projects/ms8607/en/latest/) for info on how to use it.

1.0.14

To use in CircuitPython, simply install the [Adafruit CircuitPython Bundle](https://circuitpython.org/libraries).

To use in CPython, `pip3 install adafruit-circuitpython-ms8607`.

Read the [docs](http://circuitpython.readthedocs.io/projects/ms8607/en/latest/) for info on how to use it.

1.0.13

To use in CircuitPython, simply install the [Adafruit CircuitPython Bundle](https://circuitpython.org/libraries).

To use in CPython, `pip3 install adafruit-circuitpython-ms8607`.

Read the [docs](http://circuitpython.readthedocs.io/projects/ms8607/en/latest/) for info on how to use it.

1.0.12

To use in CircuitPython, simply install the [Adafruit CircuitPython Bundle](https://circuitpython.org/libraries).

To use in CPython, `pip3 install adafruit-circuitpython-ms8607`.

Read the [docs](http://circuitpython.readthedocs.io/projects/ms8607/en/latest/) for info on how to use it.

Page 2 of 4

© 2024 Safety CLI Cybersecurity Inc. All Rights Reserved.